Tabletop Air Hockey

I tried ebay, Amazon, and like all other big name online stores. Can anyone help or find another tabletop air hockey for the same price?

http://toys.findandcompare.com/4_2438/ai r-hockey-tables.html

2006-11-30 11:07:12 by Da9

Air Hockey Tabletop Game Sales@MicroTechSys.com

by a light cord connected to a dangling block (mass m) through a central hole. Show that the speed of the pick is given by:

v= sq. rt. of (mgR/M)

PRETTY TOUGH
PLEASE SHOW WORK. THANK YOU

tension in the string = mg
v^2=mgR/M so mg=Mv^2 / R

if Mv^2/R corresponds to your formula for centripetal force required to constrain the puck in this orbit then , providing that R is the length of string sticking out of the hole onto the table top you have solved it.

2006-10-04 11:47:31 by bulldawg771

Price: $29.99 $23.13

Contents include Air Hockey game with manual scorekeeper, 3 pucks and 4 paddles
Slide, shoot and score
Table-top game works just like in the arcade

A flat puck (mass M) is rotated in a circle on a frictionless air-hockey tabletop, and is held in this orbit by a light cord connected to a dangling block (mass m) through a central hole. Show that the speed of the puck is given by by v=sqrt(mgR/M).
Can someone please tell me how to get his? It's using the formulas for Uniform Circular Motion.

a = v²/R
fc = M*a = Mv²/R

fm = m*g

For equilibrium, fc = fm or

Mv²/R = m*g → v² = mgR/M

2010-09-21 18:47:18 by Kenny

Price: $79.00 $79.00

Sturdy MDF hardwood frame sits on any table type
UL-approved, 100 cfm air-powered motor
ABS puck catcher allows for quick puck return

A flat puck (mass M) is rotated in a circle on a frictionless air-hockey tabletop, and is held in this orbit by a light cord connected to a dangling block (mass m) throught a central hole. Show that the speed of the puck is given by:
v (velocity) = squareroot (mgR/M)

I'm not quite sure what the question is asking for. Thank you for your help.

The dangling mass will not move and the puck will keep rotating in its orbit, . This implies that the centripetal force that keeps the puck in a circular orbit is just the weight of the dangling mass, this is

Fc = mg

Now, centripetal force on the puck is equal to the mass of the puck times the centripetal acceleration, or

Fc = M ac

centripetal acceleration is related to the tangential velocity of the puck as

ac = V^2 / R

where R is the radius of the orbit. Then we have

Fc = M ac =M omega^2 R = M V^2 / R

and, thus

M V ^2 / R = mg

and, solving for V, we get

V = SQRT ( m g R / M )

QED.

2008-10-14 23:34:13 by vampire

A flat puck(mass M) is rotated in a circle on a frictionless air-hockey tabletop, and is held in this orbit by a light cord connected to a dangling block (mass m) through a central hole as shown in:
http://img842.imageshack.us/img842/2913/ fysikfraga.gif

Show that the speed of the puck is given by:

v= square root of mgR/M

(i did the picture myself on paint, the dotted lines are supposed to represet its circular motion.. hope its okay..)

HELP IS EXTREMELY APPRECIATED!
Maybe this picture is more clear:
http://img832.imageshack.us/img832/2913/ fysikfraga.gif

The hanging mass (m) is in equilibrium, so that means:

Tension in string = weight of block = mg

The string's tension is providing the centripetal force for the puck:

Tension in string = centripetal force

F = Ma, so:

centripetal force = M × (puck's acceleration)

Anything moving in a circle at constant speed has acceleration v²/R, so:

puck's acceleration = v²/R

Combine all the above equations, then solve for "v"

2010-10-27 09:00:09 by tswgnaget